Concept stop · What is it?

Equations of Curves in Polar Coordinates

In the Chinese book: 极坐标系下曲线的方程

ρ = f(θ) is a point on a turning ray. Check symmetry, range, period; then plot.

📖 §6.3 of 《解析几何》

Before this stop, visit:Polar Coordinates (Concept)

Hands first, words secondPress “Turn the ray” and watch the point on the ray trace out the cardioid. Then switch to “Four-petal rose”. Which petals are drawn with negative ?

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Try this

In polar coordinates, the curve of an equation is the set of points that satisfy it, and a point is on the curve as soon as one of its polar names satisfies the equation. The most common form is : let a ray start on the polar axis and turn counterclockwise; when it reaches , mark the point on the ray with .

  1. Choose “Circle through the pole”, , and turn the ray. Why is the curve finished once reaches ? For in , which side of the ray is the point on?
  2. Choose “Four-petal rose”. In what order do the four petals appear? Which two are dashed ()?
  3. Choose “Limaçon with inner loop”. For which range of is the inner loop drawn? What is the sign of then?
  4. Choose “Archimedean spiral”. By how much does grow with each turn?
  5. For the cardioid, press the three symmetry checks one after another. Which one shows ✓? Does the way the dashed curve (the mirror image) sits on the original agree with that verdict?

A few basic equations can be read straight off the picture:

  • The line through the pole with angle of inclination : ( can be positive or negative, so one ray becomes the whole line).
  • The line whose perpendicular from the pole has length and direction angle : .
  • The circle with center at the pole and radius : ; the circle through the pole with center on the polar axis: .

Predict first

How many “petals” does the graph of have?

Choose an answer first; then you can see the result.

Why

In rectangular coordinates the equation of a “circle through the origin” has three parameters and does not look nice. In polar coordinates all it takes is one right triangle.

Example: the polar equation of the circle with center (2, 0) and radius 2

Step 1 / 5
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  1. Find a special segment

    The circle passes through the pole and meets the polar axis again at , so is a diameter. Take any point on the circle.

To graph a general , analyze first and plot afterwards. The book’s order is: symmetry → range (the largest , the directions where ) → period → table of values and plotting. Be careful with the symmetry tests:

Analysis: is ρ = 2 sin 2θ symmetric about the polar axis?

Step 1 / 3
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  1. The first substitution

    The mirror image of in the polar axis can be written as . Substituting: . The equation has changed.

Remove one condition

Break it

Counterexample lab: remove one condition

Conclusion: is a four-petal rose

Draw by the rule: for , and the point lands in the fourth quadrant. After a full turn, all four petals are there.

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Practice

Exercise 1Basic

Write the line in the form (, ). If , find .

Exercise 2Basic

The curve is a circle. What is its radius?

Exercise 3Advanced

How many petals does the graph of have?

Exercise 4Challenge

Every chord of the cardioid that passes through the pole (with both ends on the curve) has the same length. What is it?

Mistake Museum · Exhibits from this stop

Before you leave, look at the traps other people fell into here.See every exhibit in the museum →

Exhibit

One substitution fails, so you conclude there is no symmetry

The wrong step: : replacing by gives . The equation changed, so the curve is not symmetric about the polar axis.
What went wrong? Think first, then open

Diagnosis The mirror image of in the polar axis can be written as , but also as , and a point of the curve may satisfy the equation under only one of its names. Substitute the second form: . The equation is unchanged, so the curve is in fact symmetric.

The right step: Equation unchanged after a substitution ⇒ definitely symmetric. Equation changed ⇒ no conclusion yet: try the other form, or look at the graph and test points.

“A substitution test is sufficient, not necessary”

Exhibit

Letting θ run only from 0 to 2π and thinking the curve is complete

The wrong step: has period , but one full turn of the polar angle is , so letting go from to draws the whole curve.
What went wrong? Think first, then open

Diagnosis and point the same way, but : changes sign and the point lands on the other side. Drawing only loses half the curve.

The right step: To graph , let run through a full period of (here ), or first prove that the second half is a mirror image of the first.

“One turn of the ray is not one period of the equation”