Concept stop · What is it?

How Curves and Equations Correspond

In the Chinese book: 曲线与方程的对应关系

Got the equation? Now check purity (no extras) and completeness (none missed).

📖 §9.1 of 《解析几何》

Before this stop, visit:On Extremum Problems (Method)

Hands first, words secondDrag the slider slowly to turn the line through , and watch where the small dots (the true chord midpoints) land. Can they fill the whole dashed circle?

Loading figure…

Try this

“The equation of the curve is ” demands that two things both be true:

  • Purity: the points of the curve all satisfy the equation. Put the other way round, every point given by a solution of the equation satisfies the condition: no extra points have slipped in;
  • Completeness: every point that satisfies the condition is on the curve: not a single one is missed.

In the widget, the small dots are the locus points the mechanism “really” produces, and the dashed curve is an equation somebody derived. is your test point, and two readouts check “does it satisfy the condition?” and “does it satisfy the equation?” separately.

  1. Choose “Chord midpoints” and drag the slider from to . Which part of the dashed circle do the dots cover? Beyond what does the line stop cutting the circle?
  2. Press “” and “ itself”. What are the verdicts?
  3. Choose “Right-angle vertex” and drag the slider back and forth. What happens at ? Then send to .
  4. Choose “Equidistant from the axes” and drag the slider through its range. How many lines do the dots draw? How many dashed lines are there? Send to .
  5. Of the four verdicts (genuine, extra, missing, unrelated), which one shows the equation is not pure? Which one shows it is not complete?

Predict first

Lines through cut chords from the circle , and the chord midpoints lie on the circle . How much of that circle do they occupy?

Choose an answer first; then you can see the result.

Why

The standard procedure for a locus problem is: set up coordinates and a moving point → write the condition → turn it into an equation → check. The last step is exactly the check of purity and completeness. Here is a complete run.

Example: lines through P₀(4, 0) cut the circle x² + y² = 4; find the locus of the chord midpoint M

Step 1 / 5
Loading figure…
  1. Find the condition

    The line joining the midpoint of a chord to the center is perpendicular to the chord: . So , and lies on the circle with diameter .

Notice that the final range was dug out of the condition, not out of the equation: the equation itself knows nothing about the given circle. That is exactly why purity has to be checked separately.

Practice

Exercise 1Basic

, . The locus of points with is the circle with some points removed. How many points are removed?

Exercise 2Basic

How many lines make up the locus of points whose distance to the -axis is times their distance to the -axis?

Exercise 3Advanced

Chords of the circle are drawn through the interior point . The locus of their midpoints is a complete circle. What is its radius?

Exercise 4Challenge

Lines through cut chords from the circle . The locus of the chord midpoints is the arc of with . Find .

Mistake Museum · Exhibits from this stop

Before you leave, look at the traps other people fell into here.See every exhibit in the museum →

Exhibit

Removing an absolute value and keeping only one case

The wrong step: The locus of points equidistant from the -axis and the -axis: , so .
What went wrong? Think first, then open

Diagnosis is equivalent to or . Writing only leaves out the points in the second and fourth quadrants (such as ), which satisfy the condition but are not on the curve: completeness fails.

The right step: The locus is the two lines and , which can be written together as .

“At every step ask, “Is this an equivalence?””

Exhibit

Counting A and B in the locus of a right-angle vertex

The wrong step: With and , the locus of points with has equation .
What went wrong? Think first, then open

Diagnosis When coincides with , the “line ” does not even exist, let alone being perpendicular to anything. and lie on the circle but do not satisfy the condition: purity fails.

The right step: The locus is the circle without the two points , written .

“Where the figure in the condition degenerates, that point does not count”