Try this
- For , press “Fold on the y-axis”: does the dashed copy land on the original graph? What about “Half-turn about O”?
- Drag the probe . Point sits at and point at . For an odd function, how are the lengths and directions of the two vertical segments related?
- Open “Change coefficients and domain” and keep only (the term) and (the constant). Which light is on now? What if you keep only and ?
- Change the left end of the domain from to . The formula has not changed, so why did both lights go out?
Let the domain of be symmetric about the origin. If for every , then is an even function; if for every , it is an odd function.
For polynomials only the degrees matter: with only even-degree terms (constants included) the function is even; with only odd-degree terms it is odd.
Predict first
is an odd function on , and for . Find .
is outside the range where the formula is given, but its “mirror image” is inside: .
An odd function satisfies , so .
You get more for free: for we have , so ; and since is in the domain, . Once you know an odd function on “one half”, the other half is completely determined.
Why: every function splits into an even part and an odd part
As long as the domain is symmetric about the origin,
Example: write f(x) = x³ + x² − 2x + 1 as an even function plus an odd function
Step 1 / 5- It is neither odd nor even
Fold it: the dashed copy does not match the graph. Turn it half a turn: does not match either. Both lights show ✗.
Remove one condition
Break it
Counterexample lab: remove one condition
Conclusion: is an even function ← still true?
The domain is . For every , and are at the same height, and the folded copy matches the graph exactly.
Same formula ; only the domain changes to . Drag the probe to : makes sense, but does not. “ for every ” cannot hold from the very start.
So parity is a property of the function, not just of the formula: the same formula on a different domain can give a different answer.
Practice
The function is even. Find .
is an odd function on , and for . Find .
, and . Find .
Write as the sum of an even function and an odd function (both with domain ). Find .