Concept stop · What is it?

Odd and Even Functions

In the Chinese book: 奇偶性

Even folds onto itself, odd survives a half-turn; any f is even + odd.

📖 §2.1 of 《函数与函数方程》

Before this stop, visit:Functions (Concept)

Hands first, words secondPress “Fold on the y-axis”, then “Half-turn about O”, and see where the dashed copy lands. Then drag the probe and compare the heights of the points and .

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Try this

  1. For , press “Fold on the y-axis”: does the dashed copy land on the original graph? What about “Half-turn about O”?
  2. Drag the probe . Point sits at and point at . For an odd function, how are the lengths and directions of the two vertical segments related?
  3. Open “Change coefficients and domain” and keep only (the term) and (the constant). Which light is on now? What if you keep only and ?
  4. Change the left end of the domain from to . The formula has not changed, so why did both lights go out?

Let the domain of be symmetric about the origin. If for every , then is an even function; if for every , it is an odd function.

For polynomials only the degrees matter: with only even-degree terms (constants included) the function is even; with only odd-degree terms it is odd.

Predict first

is an odd function on , and for . Find .

Choose an answer first; then you can see the result.

Why: every function splits into an even part and an odd part

As long as the domain is symmetric about the origin,

Example: write f(x) = x³ + x² − 2x + 1 as an even function plus an odd function

Step 1 / 5
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  1. It is neither odd nor even

    Fold it: the dashed copy does not match the graph. Turn it half a turn: does not match either. Both lights show ✗.

Remove one condition

Break it

Counterexample lab: remove one condition

Conclusion: is an even function

The domain is . For every , and are at the same height, and the folded copy matches the graph exactly.

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Practice

Exercise 1Basic

The function is even. Find .

Exercise 2Basic

is an odd function on , and for . Find .

Exercise 3Advanced

, and . Find .

Exercise 4Challenge

Write as the sum of an even function and an odd function (both with domain ). Find .

Mistake Museum · Exhibits from this stop

Before you leave, look at the traps other people fell into here.See every exhibit in the museum →

Exhibit

The graph of an odd function always passes through the origin

The wrong step: is odd, so and the graph passes through the origin.
What went wrong? Think first, then open

Diagnosis is odd, but is not in its domain, so the graph does not pass through the origin at all. “” assumes that is in the domain.

The right step: The correct statement: if the domain of an odd function contains , then gives .

“Before you use f(0), ask whether 0 is in the domain”

Exhibit

Simplifying first, then deciding odd or even

The wrong step: , so is even.
What went wrong? Think first, then open

Diagnosis Simplifying threw away a restriction on the domain: the original function needs . So is in the domain but is not. The domain is not symmetric about the origin, so the function can be neither odd nor even.

The right step: The first step in deciding parity is always to check whether the domain is symmetric about the origin. Here it is not, so is neither odd nor even.

“No symmetric domain, no parity”