In one sentence
A coloring is a classification: sort the objects into a few classes, chosen cleverly so that every tile, every move or every structure touches a fixed number of objects of each class.
A question about the endlessly many ways of “placing things” then becomes a single count: count how many cells each color has, and you know which things can never be done. Coloring is also often used to prove that something “must exist”: however you split into two classes, one class hides some structure.
Predict first
Can a 10×10 board be covered exactly by strips of size 1×4?
No. The number of cells matches, but the colors do not. Look at it step by step below.
Example: a 10×10 board and 1×4 strips
Step 1 / 4- Just try to tile it
Lay two strips across each row, filling the first columns; in the two right-hand columns, lay two strips down each. That is strips, and a 2×2 square is left in the bottom-right corner, where no 1×4 strip fits.
The last step puts the strips back: the four uncovered cells are exactly A , B , C , D , which is minus each.
Stop 1 · Partitions of a set (Vol. 1)
Splitting into two classes is the same as coloring each number with one of two colors. The question “does one class always contain ?” is a search for a monochromatic structure.
Example: however {1, 2, 3, 4, 5} is split into two classes, one class contains x, y, x + y (x = y allowed)
Step 1 / 4- Say 1 is red
Suppose it can be avoided. , so must be blue.
Stop 2 · The principle of classification: coloring lattice points by parity (Vol. 1)
Color each lattice point with one of four colors according to . The midpoint of two points of the same color is again a lattice point.
Example: among any 5 lattice points in the plane, two have a midpoint that is also a lattice point
Step 1 / 3- Four colors
Classify by the parity of the coordinates: (even, even), (even, odd), (odd, even), (odd, odd).
Stop 3 · Existence in sequences (Vol. 5)
If are colored with two colors, must there be a monochromatic three-term arithmetic progression?
Predict first
Can be colored red and blue so that there is no monochromatic three-term arithmetic progression?
Yes: red, blue, red, blue. Check it yourself in the widget below, then set to and try again.
Example: every two-coloring of 1, 2, …, 9 has a monochromatic three-term arithmetic progression
Step 1 / 4- Look at 4 and 6
Suppose it can be avoided. First, are and the same color? If both are red, then , and force all to be blue, but is itself an arithmetic progression. Contradiction.
Practice
The cell in row , column of a 6×6 board ( counted from ) gets color number . How many cells have remainder ? (This shows that a 6×6 board cannot be covered by 1×4 strips.)
Split into two classes so that neither class contains with ( counts too). What is the largest possible ?
Color with two colors so that there is no monochromatic three-term arithmetic progression. What is the largest possible ?
An 8×8 board is covered by strips of size 1×3 and single 1×1 square. On how many different cells can the single square be?